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Question

If ¯¯¯a=¯i+¯j+¯¯¯k,¯¯b=2¯i3¯j+¯¯¯k, then ¯¯¯aׯ¯b|¯¯¯aׯ¯b|+¯¯bׯ¯¯a|¯¯bׯ¯¯a|=

A
¯¯¯0
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B
2¯i+¯j2¯¯¯k
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C
¯i+¯j+2¯¯¯k
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D
¯i+2¯j¯¯¯k
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Solution

The correct option is B ¯¯¯0
¯¯¯aׯ¯b=(¯¯bׯ¯¯a)
Also, |¯¯¯aׯ¯b|=|(¯¯bׯ¯¯a)|
Thus, the denominators become equal and the numerator adds up to 0.
Hence the answer becomes 0.

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