If a-b2 - a-b2 - 144 and -a-4- then -b- is equal to

The correct option is D 3 Since, (a×b)^2 + (a.b)^2 = 144 If angle between a and b is θ .then |a|^2|b|^2sin^2θ+|a|^2|b|^2cos^2θ= ...

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Applications of Cross Product

If a×b2 + a...

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If $(¯ ¯ ¯ a \times ¯ ¯ b)^{2} + (¯ ¯ ¯ a \cdot ¯ ¯ b)^{2} = 144$ and $| a | = 4$ , then $| b |$ is equal to

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| \to a \times \to b |^{2} + (\to a \cdot \to b)^{2} = 144

| \to a | = 4

| \to b | =

If $(\to a \times \to b)^{2} + (\to a . \to b)^{2} = 144$ and $| \to a |$ , then $| \to a |$ =

a + b = 8, a - b = 4

a^{2} + b^{2}

If {|\vec{a} \times \vec{b}|}^{2} + {|\vec{a} \cdot \vec{b}|}^{2} = 144 and |\vec{a}| = 4, then |\vec{b}|

6, 10, 7, 13, a, 12, b, 12

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\frac{37}{4}

(a - b)^{2}

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