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Question

If ¯¯¯¯¯¯¯¯AB=2i3j+k, ¯¯¯¯¯¯¯¯CB=i+j+k, ¯¯¯¯¯¯¯¯¯CD=4i7j then ¯¯¯¯¯¯¯¯¯AD=

A
5i+11jk
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B
5i11j
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C
5i+11j
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D
5i+11j
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Solution

The correct option is C 5i11j
¯¯¯¯¯¯¯¯¯AD=¯¯¯¯¯¯¯¯AB+¯¯¯¯¯¯¯¯BC+¯¯¯¯¯¯¯¯¯CD=2ˆi3ˆj+ˆkˆiˆjˆk+4ˆi7ˆj=5ˆi11ˆjOptionBiscorrectanswer.

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