If →a1,→b1,→c1 is the reciprocal system of vector triad of →a,→b,→c, then (→a+→b)⋅→a1+(→b+→c)⋅→b1+(→c+→a)⋅→c1=
A
0
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B
1
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C
2
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D
3
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Solution
The correct option is D3 We know, for the reciprocal system, →a1=→b×→c[→a→b→c]
Similarly, →b1=→c×→a[→a→b→c]
and →c1=→a×→b[→a→b→c]
Hence, (→a+→b)⋅→a1+(→b+→c)⋅→b1+(→c+→a)⋅→c1=Σ(→a+→b)⋅→b×→c[→a→b→c]=∑→a⋅(→b×→c)+→b⋅(→b×→c)[→a→b→c]=(1+0)+(1+0)+(1+0)=3