If →a1,→b1,→c1 is the reciprocal system of vector triad of →a,→b,→c, then →a.→b1+→b.→c1+→c.→a1=
A
0
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B
1
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C
2
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D
3
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Solution
The correct option is A0 We know, for the reciprocal system, →a1=→b×→c[→a→b→c]
Similarly, →b1=→c×→a[→a→b→c]
and →c1=→a×→b[→a→b→c]
Hence →a.→b1+→b.→c1+→c.→a1=→a.(→c×→a)[→a→b→c]+→b.(→a×→b)[→a→b→c]+→c.(→b×→c)[→a→b→c] =0+0+0=0