If -a-2 and -b-3- then -a-b-2-a-b-2 is equal to

The correct option is C 36Solution:Given that: |a|=2 and |b|=3 Then, |a×b|^2+|a.b|^2=|a|^2|b|^2sin^2θ+|a|^2|b|^2cos^2θ =|a|^2|b|^2(sin^2θ+co ...

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Basic Inverse Trigonometric Functions

If |a|=2 an...

Question

If $| \to a | = 2$ and $| \to b | = 3$ , then $| \to a \times \to b |^{2} + | \to a . \to b |^{2}$ is equal to

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| a \times b | = 4 a n d | a . b | = 2, t h e n {| a |}^{2} {| b |}^{2}

I

| ¯ ¯ ¯ a . ¯ ¯ b | = | ¯ ¯ ¯ a \times ¯ ¯ b |

(¯ ¯ ¯ a . ¯ ¯ b) = \frac{π}{4}

II

| ¯ ¯ ¯ a . ¯ ¯ b |^{2} = | ¯ ¯ ¯ a \times ¯ ¯ b |^{2}

(¯ ¯ ¯ a, ¯ ¯ b) = \frac{3 π}{4}

∣ ∣ \to a ∣ ∣ = 2

∣ ∣ ∣ \to b ∣ ∣ ∣ = 3

\to a . \to b = 0,

(\to a \times (\to a \times (\to a \times (\to a \times \to b))))

2^{a} = 3

9^{b} = 4

a . b

| a \times b |^{2} + (a . b)^{2} = p | b |^{2}

p =

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