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Question

If a=2^i+3^j4^k,b=^i+^j+^k and c=4^i+2^j+3^k, then a×(b×c)=

A
10
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B
1
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C
2
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D
5
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Solution

The correct option is D 5
We know thata×(b×c)=(ac)b(ab)c
(ac)b(ab)c=2(^i+^j+^k)(1)(4^i+2^j+3^k)
Where, (ac)=2,(ab)=1
=|2^i^k|=4+1=5

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