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Question

If a=2^i+4^j+3^k,b=^i+^j+^k, then the scalar product and the angle between them are

A
13, cos113174
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B
20, cos12087
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C
9, cos1987
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D
9, cos19174
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Solution

The correct option is C 9, cos1987
a.b=axbx+ayby+azbz
a=2^i+4^j+3^k,b=^i+^j+^k
a.b=2+4+3a.b=9

Angle between them is given as
cosθ=a.b|a||b|=9293
θ=cos1987

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