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Question

If A=2^i+9^j+4^k and B=6^i+^j^k, then 3AB is


A
13^i+^j26^k
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B
13(^i+^j+^k)
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C
26(^i+^k)
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D
13(2^j+^k)
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Solution

The correct option is D 13(2^j+^k)
A=2^i+9^j+4^k
3A=6^i+27^j+12^k
B=6^i^j+^k
So, 3AB=6^i+27^j+12^k6^i^j+^k
=0^i+26^j+13^k
3AB=13(2^j+^k)

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