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Question

If a=2^i+^j+3^k and b=3^i+5^j2^k, then find a×b.

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Solution

a=2^i+^j+3^k and b=3^i+5^j2^k

a×b=∣ ∣ ∣^i^j^k213352∣ ∣ ∣

= ^i(17)^j(13)+^k(103)

= 17^i+13^j+7^k

a×b=(17)2+(13)2+(7)2

= (289+169+49)

= 507=133 units.

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