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Question

If a=2^i^j+^k,b=^i+^j2^k and c=^i+3^j(λ2+3λ)^k, where λ is a constant and a is perpendicular to cλb, then sum of the different values of λ is

A
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Solution

The correct option is A 1
Given : a=2^i^j+^k,b=^i+^j2^k and c=^i+3^j(λ2+3λ)^k

As, a is perpendicular to cλb, then
a(cλb)=0acλab=023(λ2+3λ)λ(212)=0λ2+2λ+1=0(λ+1)2=0λ=1

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