If -a- - 2- -b- - 5 and -a-b- - 8- then -a-b- is equal to

Given: |a| = 2, |b| = 5, |a× nbsp;b| = 8 We know that |a×b|^2 = | nbsp; a|^2|b|^2 (a·b)^2 ⇒ (a·b)^2 = 2^2·5^2 8^2 = 36 ∴ nbsp;a. nbsp;b = ± 6 ...

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Work Done as Dot Product

If |a| = 2, |...

Question

If $| \to a | = 2, | \to b | = 5$ and $| \to a \times \to b | = 8,$ then $| \to a \cdot \to b |$ is equal to

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Similar questions

| \to a | = 5, | \to a - \to b | = 8

| \to a + \to b | = 10

| \to b |

| \to a | = 5, | \to a - \to b | = 8

| \to a + \to b | = 10

| \to b |

| \to A | = 2, | \to B | = 5

| \to A \times \to B | = 8

A

B

\to A . \to B

| \to a | = 2

| \to b | = 3

| \to a \times \to b |^{2} + | \to a . \to b |^{2}

| \to a \times \to b | = 4

| \to a \cdot \to b | = 2

| \to a |^{2} | \to b |^{2}

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