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Question

If a=(2,1,1),b=(1,1,0),c=(5,1,1), then the unit vector parallel to a+bc in the opposite direction is

A
(2^i+^j2^k3)
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B
(2^i^j+2^k3)
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C
(^i+2^j^k6)
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D
(^i2^j+^k6)
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Solution

The correct option is B (2^i^j+2^k3)
Given a=(2,1,1),b=(1,1,0),c=(5,1,1)
a+bc=(2^i+^j^k)+(^i^j+0^k)(5^i^j+^k)
a+bc=2^i+^j2^k
Magnitude of the vector is 4+1+4=3
So the unit vector in the opposite direction =(2^i+^j2^k3)
Required unit vector =(2^i^j+2^k3)

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