If A -3 -4 - and B -6 -6 -3- find the angle between loverrightarrow A - and - overrightarrow - B -cos- 37 -0-4 - 5 A- 23-B- 16- 70D- none

The correct option is C 7^o tan θ_A=43⇒θ_A = 53^∘ tan θ_B=6 √(3)6⇒θ_B = 60^∘ θ_BA=7^∘ ...

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Vector Component

If A =3 î+4 ĵ...

Question

If $\to A = 3^i + 4^j a n d \to B = 6^i + 6 \sqrt{3}^j$ , find the angle between $\to A a n d \to B (c o s 37^{o} = 4 / 5)$

23^{o}

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16^{o}

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7^{o}

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none

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\to A = 3^i + 4^j a n d \to B = 6^i + 6 \sqrt{3}^j

\to A a n d \to B (c o s 37^{o} = 4 / 5)

\to A = 3^i + 4^j

\to B = \sqrt{3}^i -^j

\to A

\to B

30^{\circ}

| \to A \times \to B |

If $(\to A & \to B)$ are two vectors then find $(\to A + 2 \to B) . (2 \to A - 3 \to B)$ .If $θ$ is the angle between them.

\to A = 3^i + 4^j

\to B = \sqrt{3}^i -^j

\to A

\to B

30^{\circ}

| \to A \times \to B |

\to A = 6^i - 15^j

\to B = - 3^i + 11^j

\to A + \to B

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