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Question

If A=3^i+4^j, B=3^i^j and angle between A and B is 30. Find |A×B|

A
2
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B
5
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C
3
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D
4
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Solution

The correct option is B 5
We know that
|A×B|=|A||B|sinθ
We have
|A|=32+42=5 and
|B|=(3)2+(1)2=2
Thus,
|A×B|=|A||B|sinθ=5×2×sin30=5

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