If A - 3 - - 4 - then what is unit vector along A -

According to the definition, Unit vector along nbsp;A, (Â) = A|A| Now magnitude of A = √((3)^2+(4)^2)= 5. nbsp; Hence, we have Â =A5 nbsp;=3 î+4ĵ5 =35î ...

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Standard XIII

Physics

Unit Vectors

If A = 3 î + ...

Question

If $\to A$ = 3 $^i$ + 4 $^j$ , then what is unit vector along $\to A$ ?

\frac{3}{5}^i

\frac{4}{5}^j

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\frac{4}{5}^i

\frac{3}{5}^j

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\frac{5}{4}^i

\frac{5}{3}^j

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\frac{5}{3}^i

\frac{5}{4}^j

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Solution

The correct option is A $\frac{3}{5}^i$ + $\frac{4}{5}^j$
According to the definition,
Unit vector along $\to A$ , $(^A)$ = $\frac{\to A}{| \to A |}$

Now magnitude of $\to A$
= $\sqrt{(3)^{2} + (4)^{2}} = 5.$

Hence, we have
$^A$ $= \frac{\to A}{5}$
$= \frac{3^i + 4^j}{5}$
$= \frac{3}{5}^i$ + $\frac{4}{5}^j$

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If →A = 3 ^i + 4 ^j, then what is unit vector along →A ?

The correct option is A 35^i + 45^jAccording to the definition, Unit vector along →A, (^A) = →A|→A| Now magnitude of →A = √(3)2+(4)2=5. Hence, we have ^A =→A5 =3^i+4^j5 =35^i + 45^j

If $\to A$ = 3 $^i$ + 4 $^j$ , then what is unit vector along $\to A$ ?