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Question

If a=3^j4^k
b=2^i^j+2^k
and c is directed along the direction parallel to angle bisector of a and b and the projection of c on d is of magnitude 109 where d=4^i4^j+7^k then |c|2 is

A
81
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B
120
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C
108
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D
150
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Solution

The correct option is B 120
direction of angle bisector of a and b can be calculated as
a|a|+b|b|
(because resultant of unit vector will lie in direction parallel to angle bisector)
=3^j4^k(3)2+(4)2+2^i^j+2^k(2)2+(1)2+(2)2
=3^j4^k5+2^i^j+2^k3
=10^i+4^j2^k15
c=λ×10^i+4^j2^k15
and also
c.d|d|=109
(λ×10^i+4^j2^k15).(4^i4^j+7^k(4)2+(4)2+(7)2)=109
λ×(401614)15×9=109
λ=15
c=15×10^i+4^j2^k15
c=10^i+4^j2^k
|c|2=120





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