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Question

If A=4^i2^j+6^k and B=^i2^j3^k the angle which AB makes with x-axis is

A
cos1(110)
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B
cos1(210)
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C
cos1(110)
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D
cos1(15)
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Solution

The correct option is C cos1(110)
A=4^i2^j+6^k & B=^i2^j3^k
AB=3^i+9^k
Let x - axis = ^i
cos θ=(3^i+9^k).(^i)32+92
cos θ=390
θ=cos1110

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