If →a and →b are two non zero vectors such that →a×→b=→b×→a, then
A
→a⋅→b=0
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B
→a=k→b, where k is a scalar quantity
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C
→a and →b are always unlike vectors
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D
→a and →b are always equal vectors
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Solution
The correct option is B→a=k→b, where k is a scalar quantity Given, →a×→b=→b×→a →a×→b=−(→a×→b) ⇒2(→a×→b)=0 ⇒(→a×→b)=0
Hence, →a is parallel to →b →a=k→b, where k is a scalar quantity