If $\to a =^i + 2^j + 2^k, | \to b | = 5$ and the angle between $\to a$ and $\to b is \frac{π}{6}$ then the area of the triangle formed by these two vectors as two sides is

\frac{15}{2}

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15

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\frac{15}{4}

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\frac{15 \sqrt{3}}{2}

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Solution

The correct option is C $\frac{15}{4}$
$Δ = \frac{1}{2} | \to a \times \to b | = \frac{1}{2} | | \to a | | \to b | sin θ | = \frac{1}{2} \times 3 \times 5 \times sin (\frac{π}{6}) = \frac{15}{4}$

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If $\to a = i + 2 j + 2 k, | \to b | = 5$ and the angle between $\to a$ and $\to b$ is $\frac{π}{6}$ , then the area of the triangle formed by these two vectors as two sides is

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and the angle between

\to a

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\frac{π}{6}

, then the area of the triangle formed by these two vectors as two sides is

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and the angle between

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Q. If two adjacent sides of a triangle are represented by vectors

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then the area of triangle.

If $\to a = i + 2 j + 2 k, | \to b | = 5$ and the angle between $\to a$ and $\to b$ is $\frac{π}{6}$ , then the area of the triangle formed by these two vectors as two sides is

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If →a=^i+2^j+2^k, |→b|=5 and the angle between →a and →b is π6 then the area of the triangle formed by these two vectors as two sides is

The correct option is C 154Δ=12|→a×→b|=12||→a||→b|sinθ|=12×3×5×sin(π6)=154

If $\to a =^i + 2^j + 2^k, | \to b | = 5$ and the angle between $\to a$ and $\to b is \frac{π}{6}$ then the area of the triangle formed by these two vectors as two sides is

The correct option is C $\frac{15}{4}$
$Δ = \frac{1}{2} | \to a \times \to b | = \frac{1}{2} | | \to a | | \to b | sin θ | = \frac{1}{2} \times 3 \times 5 \times sin (\frac{π}{6}) = \frac{15}{4}$