If →a=^i+^j and →b=−^j+2^k. Find (→a−→b).(→a+2→b).
A
6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
−6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
9
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
−9
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D−9 Given, →a=^i+^j and →b=−^j+2^k →a−→b=(^i+^j)−(−^j+2^k)=^i+2^j−2^k
and →a+2→b=(^i+^j)+2(−^j+2^k)=^i−^j+4^k
Thus, (→a−→b).(→a+2→b)=(^i+2^j−2^k).(^i−^j+4^k) ⇒1−2−8=−9