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Question

If a=^i+^j^2k, b=^2i^j+^k and c=^3i^k, then find the scalars m and n such that ma+nb.

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Solution

a=^i+^j2^k
b=2^i^j+^k
c=3^i^k
ma+nb=c
m^i+m^j2m^k+2n^in^j+n^k=3^i^k
(m+2n)^i+(mn)^j+(2m+n)^k3^i^k
By equating corresponding coefficients
m+2n=3 ………….(i)
mn=0
m=n Substituting in equation (i) 3n=3 n=m=1.
2m+n=1.

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