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Question

If A=^i+^j+^k and B=2^i^j+3^k. Find the angle between A and B.

A
cos1(442)
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B
cos1(214)
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C
cos1(242)
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D
cos1(43)
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Solution

The correct option is A cos1(442)
Given, A=^i+^j+^k and B=2^i^j+3^k
We know that,
cosθ=A.B|A||B|
cosθ=(^i+^j+^k).(2^i^j+3^k)12+12+12×22+(1)2+32
cosθ=21+3(3)(14)=442
θ=cos1(442)

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