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Question

If a=^i^j+^k and b=^j^k, then find a vector c such that a×c=b and a.c=3.....

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Solution

Let c=x^i+y^j+z^kAlso, a=^i+^j+^k and ^b=^j^kFor a×c=b,∣ ∣ ∣^i^j^k111xyz∣ ∣ ∣=^j^k ^i(zy)^j(zx)+^k(yx)=^j^k zy=0 ...(i) xz=1 ....(ii) xy=1 ....(iii)Also, a.c=3(^i+^j+^k).(x^i+y^j+z^k)=3 x+y+z=3 ....(iv)
On adding Eqs.(ii) and (iii), we get
2xyz ...(v)

On solving Eqs. (iv) and (v), we get

x=53 y=531=23 and z=23Now, c=53^i+23^j+23^k =13(5^i+2^j+2^k).....


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