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Byju's Answer
Standard XII
Mathematics
Applications of Dot Product
If a = î + ...
Question
If
→
a
=
^
i
+
^
j
+
^
k
;
→
b
=
^
i
−
^
j
+
^
k
;
→
c
=
^
i
+
^
j
−
^
k
, then
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Solution
For
a
=
i
+
j
+
k
;
b
=
i
−
j
+
k
;
c
=
i
+
j
−
k
A)
a
⋅
b
+
b
⋅
c
+
c
⋅
a
=
(
1
)
+
(
−
1
)
+
(
1
)
=
1
B)
(
(
a
⋅
c
)
c
+
(
c
⋅
b
)
a
)
⋅
b
=
(
(
1
)
c
+
(
−
1
)
a
)
⋅
b
=
(
c
−
b
)
⋅
b
=
c
⋅
b
−
b
⋅
b
=
(
−
1
)
−
1
=
−
2
C)
(
a
+
2
b
)
⋅
(
a
+
(
a
⋅
c
)
b
)
=
(
a
+
2
b
)
⋅
(
a
+
b
)
=
a
⋅
a
+
2
b
⋅
b
+
a
⋅
b
+
a
⋅
2
b
=
3
+
2
+
1
+
2
=
8
D)
(
a
+
b
)
(
a
+
b
+
c
)
=
a
⋅
a
+
a
⋅
b
+
a
⋅
c
+
b
⋅
a
+
b
⋅
b
+
b
⋅
c
=
3
+
1
+
1
+
1
+
1
−
1
=
6
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0
Similar questions
Q.
If
→
a
=
^
i
+
^
j
+
^
k
,
→
b
=
^
i
+
^
j
−
^
k
,
→
c
=
^
i
−
^
j
+
^
k
,
→
d
=
^
i
−
^
j
−
^
k
then
|
(
→
a
×
→
b
)
.
(
→
c
×
→
d
)
|
=
Q.
^
i
×
(
^
j
×
^
k
)
+
^
j
×
(
^
k
×
^
i
)
+
^
k
×
(
^
i
×
^
j
)
=
Q.
If
→
a
=
^
i
+
^
j
+
^
k
,
→
b
=
^
i
+
^
j
−
^
k
,
→
c
=
^
i
−
^
j
+
^
k
and
→
d
=
^
i
−
^
j
−
^
k
, then
(
→
a
×
→
b
)
×
(
→
c
×
→
d
)
=
Q.
If
→
a
=
^
i
+
^
j
+
^
k
,
→
b
=
^
i
−
^
j
+
^
k
,
→
c
=
^
i
+
^
j
−
^
k
and
→
a
=
^
i
−
^
j
−
^
k
, then
(
→
a
×
→
b
)
×
(
→
c
×
→
d
)
is a vector orthogonal to both
Q.
A vector of magnitude
√
2
coplanar with the vectors
→
a
=
^
i
+
^
j
+
2
^
k
and
→
b
=
^
i
+
2
^
j
+
^
k
and perpendicular to the vector
→
c
=
^
i
+
^
j
+
^
k
is
(1)
−
^
i
−
^
k
(2)
^
j
−
^
k
(3)
^
i
−
^
j
(4)
^
i
+
^
k
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