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B
2(^i+2^j−^k)
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C
−^i+^j+^k
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D
^i−^j+^k
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Solution
The correct option is B2(^i+2^j−^k) Given →a=^i+^j,→b=^i+^k{{(→a×→b)×→a}×→a}×→b ={{(→a⋅→a)→b−(→b⋅→a)→a}×→a}×→b ={|→a|2(→b×→a)−(→b⋅→a)(→a×→a)}×→b =|→a|2((→b×→a)×→b−0) =|→a|2{(→b⋅→b)→a−(→a⋅→b)→b} =2{2(^i+^j)−1(^i+^k)}=2{^i+2^j−^k}