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Question

If a=^i+^j,b=^i+^k, then {{(a×b)×a}×a}×b=

A
^i+^j+^k
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B
2(^i+2^j^k)
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C
^i+^j+^k
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D
^i^j+^k
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Solution

The correct option is B 2(^i+2^j^k)
Given a=^i+^j,b=^i+^k{{(a×b)×a}×a}×b
={{(aa)b(ba)a}×a}×b
={|a|2(b×a)(ba)(a×a)}×b
=|a|2((b×a)×b0)
=|a|2{(bb)a(ab)b}
=2{2(^i+^j)1(^i+^k)}=2{^i+2^j^k}

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