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Question

If a,b and c are three non-coplanar vectors and p,q and r are vectors defined by p=b×c[abc],q=c×a[abc] and r=a×b[abc], then the value of
(a+b)p+(b+c)q+(c+a)r=

A
0
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B
1
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C
2
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D
3
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Solution

The correct option is D 3
Given that: p=b×c[abc]. q=c×a[abc], r=a×b[abc]
=(a+b).p+(b+c).q+(c+a).r
=a.p+b.p+b.q+c.q+c.r+a.r
=a.(b×c)[abc]+0+b.(c×a)[abc]+0+c.(a×b)[abc]+0
=3

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