If a-b and c are unit vectors- then the value of -a-b-2-b-c-2-c-a-2 does not exceed

|a b|^2+|b c|^2+|c a|^2 =2(|a|^2+|b|^2+|c|^2) 2(a·b+b·c+c·a) =2×3+3 [3+2(a·b+b·c+c·a)] [∵ |a|=|b|=|c|=1] =9 (|a+b+c|^2)≤9 So, maximum value is 9. ...

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Triangle Inequality

If a,b and c ...

Question

If $\to a, \to b$ and $\to c$ are unit vectors, then the value of $| \to a - \to b |^{2} + | \to b - \to c |^{2} + | \to c - \to a |^{2}$ does not exceed

6

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8

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9

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16

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Solution

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Similar questions

\to a, \to b, \to c

| \to a - \to b |^{2} + | \to b - \to c |^{2} + | \to c - \to a |^{2}

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\to c

{∣ ∣ ∣ \to a - \to b ∣ ∣ ∣}^{2} + {∣ ∣ ∣ \to b - \to c ∣ ∣ ∣}^{2} + {∣ ∣ \to c - \to a ∣ ∣}^{2}

\to a, \to b, \to c

| \to a - 2 \to b |^{2} + | \to b - 2 \to c |^{2} + | \to c - 2 \to a |^{2}

\to a, \to b

\to c

| \to a - \to b |^{2} + | \to b - \to c |^{2} + | \to c - \to a |^{2}

\to a, \to b

\to c

\to a + \to b + \to c = 0

(\to a . \to b + \to b . \to c + \to c . \to a)

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