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Question

If [a+b b+c c+a]=λ1[a b c]
and [a×b b×c c×a]=[a b c]λ2
then λ1+λ23 is (where a,b,c are non zero and non coplanar vectors)

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Solution

[a+b b+c c+a]=(a+b).((b+c)×(c+a))

=(a+b).(b×c+b×a+c×a)

=[abc]+[bca]

=2[a b c]

[a×b b×c c×a]=(a×b).((b×c)×(c×a))

=(a×b).[bca]c

=[a b c]2

λ1=2, λ2=2

λ1+λ23=1.33

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