If A - B - C and A 2- B 2- C 2- then find the angle between A and BA- 30-B- 60- 90-D- 120-

The correct option is C 900 | A + B | = | C | or A^2 + B^2 + 2AB cos θ = C^2 ⇒ AB cos θ = 0 or cos θ = 0 ∴ θ = 90^0 ...

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Summary

If A + B = C ...

Question

If $\to A$ + $\to B$ = $\to C$ and $A^{2}$ + $B^{2}$ = $C^{2}$ , then find the angle between $\to A$ and $\to B$

30⁰

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60⁰

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90⁰

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120⁰

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Solution

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If $△ A B C \sim △ P Q R$ and $∠ B = ∠ R = 60^{\circ}$ , then find $∠$ RPQ.

\frac{a^{2} - b^{2} - c^{2}}{(a - b) (a - c)} + \frac{b^{2} - c^{2} - a^{2}}{(b - c) (b - a)} + \frac{c^{2} - a^{2} - b^{2}}{(c - a) (c - b)}

\to A + \to B = \to C

| \to A | = 4, | \to B | = 5

| \to C | = \sqrt{61}

\to A

\to B

\sqrt{a^{2} + b^{2} + a b}

△_{1}, △_{2}

(b, c), (c, a), (a, b)

(a c - b^{2}, a b - c^{2}), (b a - c^{2}, b c - a^{2}), (c b - a^{2}, c a - b^{2})

\frac{△_{1}}{△_{2}} = (a + b + c)^{2}

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