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Question

If A=B+C and A,B,C has scalar magnitudes of 5, 4, 3 units respectively then the angle between A and C is

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Solution

A=B+C
AC=B
Taking self scalar product on both sides-
(AC).(AC)=(B.B)
(A.AC.AA.C+C.C)=|B|2
|A|22AC+|C|2=|B|2
522|A||C|cosθ+32=42
182(5)(3)cosθ=0
1830cosθ=0
cosθ=35
θ=cos135


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