If a-b-c are any three non-zero vectors such that a-b-c-a-b-c-0- then a-b-c-

Given (a+b)·c=(a b)·c=0 ⇒a·c+b·c=0 ⋯(i) and nbsp; a·c b·c=0 ⋯(ii) Using (i) and (ii), we get a·c=0 and b̅·c̅=0 ⇒ (a×b)×c=(a·c)·b (b·c)a=0 ...

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Linear Combination of Vectors

If a,b,c are ...

Question

If $\to a, \to b, \to c$ are any three non-zero vectors such that $(\to a + \to b) \cdot \to c = (\to a - \to b) \cdot ¯ ¯ c = 0,$ then $(\to a \times \to b) \times \to c =$

\to 0

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\to a

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\to b

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\to c

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Solution

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Similar questions

(\to a \times \to b) \times \to c = \to a \times (\to b \times \to c)

\to a, \to b

\to c

\to a \cdot \to b \neq 0, \to b \cdot \to c \neq 0,

\to a

\to c

\to a, \to b, \to c; ∣ ∣ ∣ (\to a \times \to b) \cdot \to c ∣ ∣ ∣ = ∣ ∣ \to a ∣ ∣ ∣ ∣ ∣ \to b ∣ ∣ ∣ ∣ ∣ \to c ∣ ∣

\to a, \to b

\to c

\to a + \to b + \to c = \to 0

λ = \to a \cdot \to b + \to b \cdot \to c + \to c \cdot \to a

\to d = \to a \times \to b + \to b \times \to c + \to c \times \to a

(λ, \to d)

A, B

C, | (A \times B) \cdot C | = | A | | B | | C |

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