If →a,→b,→c are non-zero, non-coplanar vectors then {→a×(→b+→c)}×{→b×(→c−→a)} is collinear with the vector(s)
A
→a+→b+→c
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B
−→a+→b+→c
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C
−→a−→b−→c
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D
→a−→b−→c
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Solution
The correct option is D→a−→b−→c {→a×(→b+→c)}×{→b×(→c−→a)}={→a×→b+→a×→c}×{→b×→c−→b×→a}={→a×→b−→c×→a}×{→b×→c+→a×→b}=(→a×→b)×(→b×→c)+(→a×→b)×(→a×→b)−(→c×→a)×(→b×→c)−(→c×→a)×(→a×→b)=[→a→b→c]→b−[→a→b→b]→c+[→a→b→b]→a−[→a→b→a]→b−[→c→a→c]→b+[→c→a→b]→c−[→c→a→b]→a+[→c→a→a]→b=[→a→b→c](→b+→c−→a)
So given vector is collinear with ±(→a−→b−→c)