The correct option is C [→c→a→b]
As →a,→b,→c are three non coplanar vectors, then (→a×→b),(→b×→c),(→c×→a) are also non coplanar.
Any vector →r can be written in terms of three non coplanar vectors as:
→r=l(→a×→b)+m(→b×→c)+n(→c×→a) where l,m,n are scalar.
Now, →r.→a=m[→a→b→c]
⇒m=→r.→a[→a→b→c]
Similarly, n=→r.→b[→a→b→c]
and l=→r.→c[→a→b→c]Hence on comparing, we have λ=[→a→b→c]