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Question

If a,b,care three non-coplanar vectors,p,q,rare non-zero vectors such thatp=b×c[abc],q=c×a[abc],r=a×b[abc], then the value of the expression (a+b+c),(p+q+r) is

A
0
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B
4
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C
2
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D
3
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Solution

The correct option is A 0
[¯¯¯a¯¯b¯¯c]0¯¯¯¯P=¯bׯc[¯¯¯a¯b¯c],¯¯¯¯Q=¯cׯ¯¯a[¯¯¯a¯b¯¯¯c]¯¯¯¯R=¯¯¯aׯb[¯¯¯a¯b¯c]Tofind(¯¯¯a+¯¯b+¯¯c).(¯¯¯p+¯¯¯q+¯¯¯r)¯¯¯a.¯¯¯p=¯¯¯a.(¯bׯc)[¯¯¯a¯b¯¯¯c]=1[¯¯¯a¯b¯¯¯c]={¯¯¯a.(¯¯bׯ¯c)}=[¯¯¯a¯b¯c][¯¯¯a¯b¯c]=1¯¯b.¯¯¯p=¯¯b.(¯bׯc)[¯¯¯a¯b¯¯¯c]=1[¯¯¯a¯b¯¯¯c]{¯¯b.(¯¯bׯ¯c)}=0¯¯c.¯¯¯p=0¯¯b.¯¯¯q=1¯¯c.¯¯¯r=1RemainingZero.

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