wiz-icon
MyQuestionIcon
MyQuestionIcon
14
You visited us 14 times! Enjoying our articles? Unlock Full Access!
Question

If a,b,care three non-coplanar vectors,p,q,rare non-zero vectors such thatp=b×c[abc],q=c×a[abc],r=a×b[abc], then the value of the expression (a+b+c),(p+q+r) is

A
0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 0
[¯¯¯a¯¯b¯¯c]0¯¯¯¯P=¯bׯc[¯¯¯a¯b¯c],¯¯¯¯Q=¯cׯ¯¯a[¯¯¯a¯b¯¯¯c]¯¯¯¯R=¯¯¯aׯb[¯¯¯a¯b¯c]Tofind(¯¯¯a+¯¯b+¯¯c).(¯¯¯p+¯¯¯q+¯¯¯r)¯¯¯a.¯¯¯p=¯¯¯a.(¯bׯc)[¯¯¯a¯b¯¯¯c]=1[¯¯¯a¯b¯¯¯c]={¯¯¯a.(¯¯bׯ¯c)}=[¯¯¯a¯b¯c][¯¯¯a¯b¯c]=1¯¯b.¯¯¯p=¯¯b.(¯bׯc)[¯¯¯a¯b¯¯¯c]=1[¯¯¯a¯b¯¯¯c]{¯¯b.(¯¯bׯ¯c)}=0¯¯c.¯¯¯p=0¯¯b.¯¯¯q=1¯¯c.¯¯¯r=1RemainingZero.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon