Let A(1,y1) and B(x2,11) be two points on the curve y=x2−2x+3.
If O is the origin, then −−→OA.−−→OB
y=x2−2x+3
⇒y1=2 when x=1 and x2−2x+3=11
⇒x2−2x−8=0
⇒x=4,−2 are the roots
∴x2=4 or −2
A=(1,2),B=(4,11) or (−2,11)
−−→OA.−−→OB=(^i+2^j).(4^i+11^j)=26
(or) (^i+2^j)(−2^i+11^j)=−2+22=20