If →A×→B=→B×→C=→C×→A then →A+→B+→C is equal to:
If →a,→b,→c are mutually perpendicular vectors of equal magnitudes, show that the vector →a+→b+→c is equally inclined to →a,→b and →c.
If the sum of a, b and c is equal to the even prime, then find the value of 24a−b−c×24b−c−a×24c−a−b.