If (→a×→b).(→c×→b)+(→a.→b)(→b.→c)=λ(→a.→c), then λ is equal to
A
|→a|2
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B
|→b|2
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C
|→c|2
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D
0
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Solution
The correct option is B|→b|2 Scalar product of four vectors (→a×→b).(→c×→b)=(→a.→c)(→b.→b)−(→a.→b)(→b.→c)
Hence, (→a×→b).(→c×→b)+(→a.→b)(→b.→c)=|→b|2(→a.→c)
comparing with, (→a×→b).(→c×→b)+(→a.→b)(→b.→c)=λ(→a.→c) ∴λ=|→b|2