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Question

If a×(b×c)+b×(c×a)=λ1a+λ2b+λ3c then λ1+λ2+λ3=

A
b.c+a.c
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B
a.c+b.c
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C
a.b+b.c+c.a
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D
none of these
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Solution

The correct option is A b.c+a.c
a×(b×c)+b×(c×a)=(a.c)b(a.b)c+(b.a)c(b.c)a=(b.c)a+(a.c)b+(b.aa.b)cλ1a+λ2b+λ3cλ1+λ2+λ3=a.cb.corb.c+a.cHence,optionAiscorrectanswer.

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