If −→B1,−→B2 and −→B3 are the magnetic field due to the wires carrying current I1,I2 and I3, then in the expression of Ampere's circuital law, ∮→B.→dl=μ0I, →B is
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Solution
In Ampere's circuital law,
∮→B.→dl=μ0Ienclosed
Ienclosed= net current passing through the loop
→B= resultant magnetic field due to all currents existing anywhere either inside or outside the loop