If $\to b$ and $\to c$ are the position vectors of the points B and C respectively, then the position vector of the point D such that $- - \to B D = 4 - - \to B C$ is

4 (\to c - \to b)

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- 4 (\to c - \to b)

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4 \to c - 3 \to b

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4 \to c + 3 \to b

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Solution

The correct option is B $4 \to c - 3 \to b$
Solution:
Given that: $- - \to B D = 4 - - \to B C$
It means $D$ divides the join of $B C$ externally in the ratio $4 : 3.$
$∴$ Position vector of $D = \frac{4 \to c - 3 \to b}{4 - 3} = 4 \to c - 3 \to b$
Hence, C is the correct option.

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