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Question

If b and c are two non-collinear unit vectors and a is any vector, then (ab)b+(ac)c+a(b×c)|b×c|2(b×c)=

A
a
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B
b
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C
c
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D
a+b+c
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Solution

The correct option is A a

Let b=^i,c=^j
|b×c|=|^k|=1
again, let a=a1^i+a2^j+a3^k
Now,

ab=a^i=a1,ac=a^j=a2
and ab×c|b×c|=a^k=a3
(ab)b+(ac)c+ab×c|b×c|(b×c)

=a1b+a2c+a3(b×c)=a1^i+a2^j+a3^k=a


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