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Question

If (b×c)×(c×a)=3c, then [b×c c×a a×b] is equal to

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Solution

Given : (b×c)×(c×a)=3c
[b c a]c[b c c]a=3c[b c a]c0=3c[b c a]=3(i)
Now,
[b×c c×a a×b]=(a×b){(b×c)×(c×a)}=(a×b)3c=3[a b c]=9
(from (i))

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