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Question

If d=xˆi+yˆj+zˆk, then which of the following equations is/are correct?
1. yx=4
2. 2z3=0
Select the correct answer using the code given below

A
1 only
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B
2 only
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C
Both 1 and 2
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D
Neither 1 nor 2
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Solution

The correct option is D Neither 1 nor 2
c is parallel to c
c=ka
c=kˆi+kˆj

b=c+d
3ˆi+4ˆk=kˆi+kˆj+xˆi+yˆj+zˆk
3ˆi+4ˆk=(k+x)ˆi+(k+y)ˆj+zˆk

k+x=3 ...(1)
k+y=0 ...(2)
z=4 ...(3)

From (2) k=y
Substituting this in equation (1),
y+x=3
yx=3

So, the answer is option (D)

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