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Question

If p=b×c[abc], q=c×a[abc] and r=a×b[abc], where a, b and c are three non-coplanar vectors, then the value of the expression (a+b+c)(p+q+r) is

A
3
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B
2
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C
1
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D
0
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Solution

The correct option is A 3
ap=a(b×c)[abc]
=a(b×c)[abc] =[abc][abc]=1

aq=a(c×a)[abc]
=a(c×a)[abc] =[aca][abc]=0

Similarly,
ar=0,bp=0,bq=1,
br=0,
cp=0,cq=0,
cr=1

(a+b+c)(p+q+r)
=ap+aq+ar
+bp+bq+br
+cp+cq+cr
=1+1+1=3

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