If →p=→b×→c[→a→b→c],→q=→c×→a[→a→b→c] and →r=→a×→b[→a→b→c], where →a,→b and →c are three non-coplanar vectors, then the value of the expression (→a+→b+→c)⋅(→p+→q+→r) is
A
3
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B
2
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C
1
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D
0
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Solution
The correct option is A3 →a⋅→p=→a⋅(→b×→c)[→a→b→c] =→a⋅(→b×→c)[→a→b→c]=[→a→b→c][→a→b→c]=1