If →p,→q are two non collinear and non zero vectors such that (b−c)→p×→q+(c−a)→p+(a−b)→q=0 where a,b,c are the lengths of the sides of triangle, then the triangle is:
A
Right angled
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B
Obtuse angled
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C
Equilateral
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D
Isosceles
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Solution
The correct option is C Equilateral →p×→q is perpendicular to both →p and →q. Hence →p, →q and →p×→q are non coplanar. ∴(b−c)→p×→q+(c−a)→p+(a−b)→q=0 ⇒b−c=c−a=a−b=0⇒a=b=c
Hence triangle is equilateral.