CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If r=3^i+2^j5^k,a=2^i^j+^k,b=^i+3^j2^k and c=2^i+^j3^k such that r=xa+yb+zc, then

A
x,y,z are in A.P.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
x,y,z are in G.P.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x,y,z are in H.P.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
y,x2,z are in A.P.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D y,x2,z are in A.P.
We have r=xa+yb+zc
3^i+2^j5^k=x(2^i^j+^k)+y(^i+3^j2^k)+z(2^i+^j3^k)3=2x+y2z,2=x+3y+z,5=x2y3zx=3,y=1,z=2

Clearly, x=y+z
y,x2,z are in A.P.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Terminology
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon