If →R=→P+→Q and →R makes an angles θ1 with →P and θ2 with →Q. Then
A
θ1 cannot be less than θ2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
If θ1<θ2 then ∣∣∣→P∣∣∣<∣∣∣→Q∣∣∣
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
If θ1<θ2 then ∣∣∣→P∣∣∣>∣∣∣→Q∣∣∣
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
If θ1=θ2 then ∣∣∣→P∣∣∣=∣∣∣→Q∣∣∣
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct options are C If θ1<θ2 then ∣∣∣→P∣∣∣>∣∣∣→Q∣∣∣ D If θ1=θ2 then ∣∣∣→P∣∣∣=∣∣∣→Q∣∣∣ →R=→P+→Q∠→R→P=θ1∠→R→Q=θ2∠→P→Q=θcosθ1=→R⋅→PRP=(→P+→Q)⋅→PRP=P2+→P⋅→QRP=P+QcosθR......(1)