If u - a - b - v - a - b and - a - - b - -2- then - u - v - is

The correct option is A 2√( 16 ( a . b #160;) #160;^ 2 ) We have u = a b , v = a + b ⇒ u × v =( a b #160;) ×( a + b ...

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Algebra of Limits

If u = a - ...

Question

If $\to u = \to a - \to b, \to v = \to a + \to b$ and $∣ ∣ \to a ∣ ∣ = ∣ ∣ ∣ \to b ∣ ∣ ∣ = 2,$ then $∣ ∣ \to u \times \to v ∣ ∣$ is

2 \sqrt{16 - {(\to a . \to b)}^{2}}

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2 \sqrt{4 - {(\to a . \to b)}^{2}}

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\sqrt{16 - {(\to a . \to b)}^{2}}

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\sqrt{4 - {(\to a . \to b)}^{2}}

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| a \times b |^{2} = (a . a) (b .) - (a . b)^{2} = a^{2} b^{2} - (a . b)^{2}

∣ ∣ ¯ ¯ ¯ a ∣ ∣ = ∣ ∣ ¯ ¯ b ∣ ∣ = 2

{(¯ ¯ ¯ a \times ¯ ¯ b)}^{2} + {(¯ ¯ ¯ a . ¯ ¯ b)}^{2} =

| a \times b |^{2} + (a . b)^{2} = p | b |^{2}

p =

{∣ ∣ ∣ \to a \times \to b ∣ ∣ ∣}^{2} + {(\to a . \to b)}^{2}

¯ ¯ ¯ a = 2 ¯ i + 2 ¯ j + ¯ ¯ ¯ k, ¯ ¯ b = 5 ¯ i + ¯ j + 2 ¯ ¯ ¯ k

(¯ ¯ ¯ a \times ¯ ¯ b)^{2} + (¯ ¯ ¯ a . ¯ ¯ b)^{2} =

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